[Django]-Django catching all URLS under a specific name



You can make use of the <path:…> path converter [Django-doc], but this requires the element to be non-empty.

using re_path

If you thus want to match paths including empty ones, you can make use of the ([^/]+/)* regex pattern:

from django.urls import re_path

urlpatterns = [
    re_path(r'^business/(?P<path>([^/]+/)*)$', views.myview, name='myview'),

and then in the view split the path:

def myview(request, path):
    path_items = path.split('/')

path_items is than a list of path elements.

Custom path converter

You can also register a custom path converter:

# app/converters.py

class EmptyPathConverter:
    regex = '([^/]+/)*'

    def to_python(self, value):
        return value.split('/')

    def to_url(self, value):
        return '/'.join(value)

and then register the path converter and use it when defining a path:

from app.converters import EmptyPathConverter
from django.urls import path, register_converter

register_converter(EmptyPathConverter, 'emptypath')

urlpatterns = [
    path('business/<emptypath:paths>', views.myview, name='myview'),

then we can use this in a view, which will already do the splitting for us:

def myview(request, paths):
    # paths is a list of strings
    # …

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