46👍
✅
No, the request is not passed to the ModelForm. You’ll need to do something like this in your view:
form = BookSubmitForm()
form.fields['book'].queryset = Book.objects.filter(owner=request.user)
# pass form to template, etc
As you said, it’s often cleaner to encapsulate this in the Form object, particularly if you have several fields that will need filtered querysets. To do this, override the forms’s __init__()
and have it accept a kwarg of request
:
class BookSubmitForm(ModelForm):
def __init__(self, *args, **kwargs):
self.request = kwargs.pop("request")
super(BookSubmitForm, self).__init__(*args, **kwargs)
self.fields["book"].queryset = Book.objects.filter(owner=self.request.user)
self.fields["whatever"].queryset = WhateverModel.objects.filter(user=self.request.user)
Then just pass request whenever you instantiate BookSubmitForm
in your view:
def book_submit(request):
if request.method == "POST":
form = BookSubmitForm(request.POST, request=request)
# do whatever
else:
form = BookSubmitForm(request=request)
# render form, etc
14👍
Extending AdamKG answer to class based views – override the get_form_kwargs
method:
class PassRequestToFormViewMixin:
def get_form_kwargs(self):
kwargs = super().get_form_kwargs()
kwargs['request'] = self.request
return kwargs
from django.views.generic.edit import CreateView
class BookSubmitCreateView(PassRequestToFormViewMixin, CreateView):
form_class = BookSubmitForm
# same for EditView
and then in forms:
from django.forms import ModelForm
class BookSubmitForm(ModelForm):
def __init__(self, *args, **kwargs):
self.request = kwargs.pop("request")
super().__init__(*args, **kwargs)
...
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