[Solved]-Add object level permission to generic view


You can do it using class-based-views:

class BlogEdit(UpdateView):
    model = Blog

    def dispatch(self, request, *args, **kwargs):
        if not request.user.has_perm('blog_permission.blog_edit'):
            return HttpResponseForbidden()
        return super(BlogEdit, self).dispatch(request, *args, **kwargs)

    # OR (for object-level perms)

    def get_object(self, *args, **kwargs):
        obj = super(BlogEdit, self).get_object(*args, **kwargs)
        if not obj.user == self.request.user:
            raise Http404 # maybe you'll need to write a middleware to catch 403's same way
        return obj


Another option is to use UserPassesTestMixin (or user_passes_test for function-based).

class UserPassesTestMixin

When using class-based views, you can use the
UserPassesTestMixin to do this.


You have to override the test_func() method of the class to
provide the test that is performed. Furthermore, you can set any of
the parameters of AccessMixin to customize the handling of
unauthorized users:

from django.contrib.auth.mixins import UserPassesTestMixin

class MyView(UserPassesTestMixin, View):

    def test_func(self):
        return self.request.user.email.endswith('@example.com')

We can now check if the self.request.user is allowed to process the details passed into the self.request.GET or self.request.POST.

class MyView(UserPassesTestMixin, View):
    raise_exception = True  # To not redirect to the login url and just return 403. For the other settings, see https://docs.djangoproject.com/en/3.2/topics/auth/default/#django.contrib.auth.mixins.AccessMixin

    def test_func(self):
        return (
            or self.request.user.has_perm('app.change_blog')
            or self.request.user.email.endswith('@company.staff.com')
            or is_requested_object_accessible(self.request.user, self.request.GET, self.request.POST)  # If you have a custom checker

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