[Fixed]-Django ChoiceField populated from database values

if you want to populate dropdown list from database, I’ll recommend you to pass all the values in single object from views.py to your template. You can do it this way:
1] fetch all the values from database:

objectlist = ModelName.objects.all()

if you want sorted list in dropdown list, Do this:

objectlist = ModelName.objects.all().order_by('fieldname')

if you want distinctlist, do this:

objectlist = ModelName.objects.distinct('fieldname')

2] Pass this render this ‘objectlist’ with template

return render(request, 'template.html', {'objectlist': objectlist})

3] In template use a select tag , and in user for loop to iterate over the objectlist.

<select>


{% for element in objectlist %}


<option value={{ element.id }}>{{ element.name }}



     </select>

value in option tag depends on what you need to process in your API

Use the ModelChoiceField Link Here

ChoiceField doesn’t support queryset

view.py :-
This is my view.py file. And create below code.

def add_customer(request):
    objectlist = Vehicle.objects.values('brand_name').distinct().order_by('brand_name')
    if request.method == 'POST':
        form = CustomerForm(request.POST)
        if form.is_valid():
            form.save()
            return redirect('/show-customers')
    else:
        form = CustomerForm()
    return render(request, 'add-customer.html', {'form':form, 'objectlist':objectlist})

Customer.html

<select name="prefer_car_model" id="id_prefer_car_model" required>
                <option value="0" selected disabled> Select Car model </option>
                {% for obj in objectlist %}
                <option value="{{ obj.brand_name }}">{{ obj.brand_name }} </option>
                {% endfor %}
            </select>

Output

In Django 2+ you can use ‘choices’ instead of ‘queryset’