[Solved]-Downloading the files(which are uploaded) from media folder in django 1.4.3

by

6👍

Just remove / after filename.

Change this:

response['Content-Disposition'] = 'attachment; filename=%s/' % smart_str(file_name)

to this:

response['Content-Disposition'] = 'attachment; filename=%s' % smart_str(file_name)
👤goromlagche

6👍

Your code is right but there is one redundant character in download:

def download(request,file_name):
    file_path = settings.MEDIA_ROOT +'/'+ file_name
    file_wrapper = FileWrapper(file(file_path,'rb'))
    file_mimetype = mimetypes.guess_type(file_path)
    response = HttpResponse(file_wrapper, content_type=file_mimetype )
    response['X-Sendfile'] = file_path
    response['Content-Length'] = os.stat(file_path).st_size
    response['Content-Disposition'] = 'attachment; filename=%s/' % smart_str(file_name) 
    return response

At last line the filename attribute has a trailing slash (/): filename=%s/

Which causes the problem. Remove this slash and it works.

👤CumaTekin

2👍

These are all not required.In HTML you can download the media file by using <a download="{video.URL}">

For example:

<button class="btn btn-outline-info">
<a href="{{result.products.full_video.url}}" download="{{result.products.full_video.url}}" style="text-decoration:None" class="footer_link">Download<i class="fa fa-download"></i></a>
</button>
👤Chethan H V

0👍

I solved the problem by replacing

response['Content-Disposition'] = 'attachment; filename=diploma_"' + str(someID) + '.pdf"'

with

response['Content-Disposition'] = 'attachment; filename="diploma_{}{}"'.format(str(someID),'.pdf')
👤Edd

0👍

import urllib, mimetypes
from django.http import HttpResponse, Http404, StreamingHttpResponse, FileResponse
import os
from django.conf import settings
from wsgiref.util import FileWrapper

class DownloadFileView(django_views):
    def get(self,request,file_name):
        file_path = settings.MEDIA_ROOT +'/'+ file_name
        file_wrapper = FileWrapper(open(file_path,'rb'))
        file_mimetype = mimetypes.guess_type(file_path)
        response = HttpResponse(file_wrapper, content_type=file_mimetype )
        response['X-Sendfile'] = file_path
        response['Content-Length'] = os.stat(file_path).st_size
        response['Content-Disposition'] = 'attachment; filename=%s/' % str(file_name) 
        return response
👤surya

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