[Fixed]-How can I tell Django templates not to parse a block containing code that looks like template tags?

24👍

As of Django 1.5, this is now handled by the built-in verbatim template tag.

In older versions of Django, the built-in way would be to manually escape each template item with the templatetag template tag ( https://docs.djangoproject.com/en/1.3/ref/templates/builtins/#templatetag ), but I suspect that that’s not what you want to do.

What you really want is a way to mark a whole block as raw (rather than interpretable) text, which requires a new custom tag. You might want to check out the raw tag here: http://www.holovaty.com/writing/django-two-phased-rendering/

5👍

There are a couple open ticket to address this issue: https://code.djangoproject.com/ticket/14502 and https://code.djangoproject.com/ticket/16318
You can find a proposed new template tag verbatim below:

"""
From https://gist.github.com/1313862
"""

from django import template

register = template.Library()


class VerbatimNode(template.Node):

    def __init__(self, text):
        self.text = text

    def render(self, context):
        return self.text


@register.tag
def verbatim(parser, token):
    text = []
    while 1:
        token = parser.tokens.pop(0)
        if token.contents == 'endverbatim':
            break
        if token.token_type == template.TOKEN_VAR:
            text.append('{{')
        elif token.token_type == template.TOKEN_BLOCK:
            text.append('{%')
        text.append(token.contents)
        if token.token_type == template.TOKEN_VAR:
            text.append('}}')
        elif token.token_type == template.TOKEN_BLOCK:
            text.append('%}')
    return VerbatimNode(''.join(text))

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