[Solved]-How to get message-id of email sent from smtplib

I found the above answer to be incredibly confusing. Hopefully the below helps others:

import smtplib
import email.message
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.base import MIMEBase
from email import encoders
import email.utils as utils

def send_html_email(subject, msg_text,
                    toaddrs=['foo@gmail.com']):
    fromaddr = 'me@mydomain.com'

    msg = "\r\n".join([
        "From: " + fromaddr,
        "To: " + ",".join(toaddrs),
        "Subject: " + subject,
        "",
        msg_text
    ])

    msg = email.message.Message()
    msg['message-id'] = utils.make_msgid(domain='mydomain.com')
    msg['Subject'] = subject
    msg['From'] = fromaddr
    msg['To'] = ",".join(toaddrs)
    msg.add_header('Content-Type', 'text/html')
    msg.set_payload(msg_text)

    username = fromaddr
    password = 'MyGreatPassword'
    server = smtplib.SMTP('mail.mydomain.com',25)
    #server.ehlo() <- not required for my domain.
    server.starttls()
    server.login(username, password)
    server.sendmail(fromaddr, toaddrs, msg.as_string())
    server.quit()