[Fixed]-How to limit field access on a model based on user type on Graphene/Django?



Assuming that you have

  1. a query defined like
    employees = graphene.List(EmployeeType)
  1. a resolver for the query like
    def resolve_employees(self, info, **kwargs):
        return Employee.objects.all()


  1. permissions on your Employee model called can_view_salary and can_edit_salary

Then you’ll need to define the EmployeeType with a value of salary that is dependent on the user. Something like

from graphene_django.types import DjangoObjectType
from myapp.models import Employee

class EmployeeType(DjangoObjectType):
    class Meta:
        model = Employee
    def resolve_salary(self, info):
        if info.context.user.has_perm('myapp.can_view_salary'):
            return self.salary
        return None

The important takeaway is that you’re creating a custom resolve function for the salary that is switching based on the value of a permission. You don’t need to create any other resolvers for first_name and last_name.


Read the documentation first. But there isn’t an example for doing an update.

In brief, here’s the approach that you can take:

  1. Create a method to set the employee in your Mutation method
class MyMutations(graphene.ObjectType):
     set_employee = SetEmployee.Field()
  1. Create a method for SetEmployee that gets the Employee object and updates it. The salary field is ignored for certain users.
class SetEmployee(graphene.Mutation):
    class Arguments:
        id = graphene.ID()
        first_name = graphene.String()
        last_name = graphene.String()
        salary = graphene.String()
    employee = graphene.Field(lambda: EmployeeType)
    def mutate(cls, root, info, **args):
        employee_id = args.get('employee_id')
        # Fetch the employee object by id
        employee = Employee.objects.get(id=employee_id)
        first_name = args.get('first_name')
        last_name = args.get('last_name')
        salary = args.get('salary')
        # Update the employee fields from the mutation inputs
        if first_name:
            employee.first_name = first_name
        if last_name:
            employee.last_name = last_name
        if salary and info.context.user.has_perm('myapp.can_edit_salary'):
            employee.salary = salary
        return SetEmployee(employee=employee)

Note: when this answer was originally written, there was no Decimal field available in Graphene Django — I avoided this issue by taking a string as an input.


Great response @MarkChackerian. However personally, I believe that returning a null value for a field on unauthorised access can be ambiguous, so I personally raise an exception from resolve method like that:

class UnauthorisedAccessError(GraphQLError):
    def __init__(self, message, *args, **kwargs):
        super(UnauthorisedAccessError, self).__init__(message, *args, **kwargs)

def resolve_salary(self, info):
        if info.context.user.has_perm('myapp.can_view_salary'):
            return self.salary
        raise UnauthorisedAccessError(message='No permissions to see the salary!')

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