[Solved]-How to save a ManyToMany field with a through relationship


You will have to explicitly save the MeetingArrival object in your view to save an intermediate model in case of a ManyToManyField with through argument.

For Django versions 2.1 and below, in case of ManyToManyField with an intermediary model, you can’t use add, create, or assignment which are available with normal many-to-many fields.

As per the Django 1.8 docs:

Unlike normal many-to-many fields, you can’t use add, create, or
assignment to create relationships.

The only way to create this type of relationship is to create
instances of the intermediate model.

So, you will have to explicitly create a MeetingArrival object in your view.

You can do it by:

def add_meeting(request): 
    add_meeting_form = AddMeetingForm(request.POST or None)
    site = Site.objects.get(user=request.user.id)

    if request.method == "POST":
        if add_meeting_form.is_valid():
            obj = add_meeting_form.save(commit=False)
            obj.site = site

            # create an instance of 'MeetingArrival' object
            meeting_arrival_obj = MeetingArrival(meeting=obj, visitor=<your_visitor_object_here>, arrival_status=True)
            meeting_arrival_obj.save() # save the object in the db


for django 1.x, it is as what Rahul said that you can’t use add, create, etc

for django 2.x, you actually can per the document here django 2.x

You can also use add(), create(), or set() to create relationships, as long as you specify through_defaults for any required fields:

beatles.members.add(john, through_defaults={'date_joined': date(1960, 8, 1)})
beatles.members.create(name="George Harrison", through_defaults={'date_joined': date(1960, 8, 1)})
beatles.members.set([john, paul, ringo, george], through_defaults={'date_joined': date(1960, 8, 1)})


When you use a through table, you need to save there manually.

MeetingArrival.objects.create( ... )


Don’t put the logic where you handle the ManyToManyField in your view, put it in your form instead, so you won’t have to repeat yourself if you use the form in multiple places.

To this end, you need to override the save method of the ModelForm.

See my more thorough answer to another question: https://stackoverflow.com/a/40822731/2863603



I did it this way, still trying to get multiple id values from the select, I think there is something wrong in my javascript

but here is python code:

class ArticuloCreateView(View):
    def __init__(self):
        self.template_name = 'articulo/formulario.html'

    def get(self, request):
        formulario = ArticuloForm()
        contexto = {
            'form': formulario,
            'operation': "Nuevo"
        return render(request, self.template_name, contexto)

    def post(self, request):
        punto_transaccion = transaction.savepoint()
        formulario = ArticuloForm(request.POST)
        almacenes = request.POST.get('almacenes', 0)
        almacenes = Almacen.objects.filter(id=almacenes)

        if formulario.is_valid():
            datos_formulario = formulario.cleaned_data
            articulo = Articulo()
            articulo.clave = datos_formulario.get('clave')
            articulo.descripcion = datos_formulario.get('descripcion')
            articulo.tipo = datos_formulario.get('tipo')
            articulo.udm = datos_formulario.get('udm')
            articulo.clave_jde = datos_formulario.get('clave_jde')

            for almacen in almacenes:
                Stock.objects.create(articulo=articulo, almacen=almacen)
            if punto_transaccion:

            return redirect(
        contexto = {
            'form': formulario,

        return render(request, self.template_name, contexto)


user_profiles = UserProfile.objects.all()

NotificationUser.objects.bulk_create([NotificationUser(user=user_profile, notification=notification) for user_profile in user_profiles])

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