[Fixed]-Reversing namespaced URLs in Django: multiple instances of the same app


Not a very nice solution, but since you use the same text for your namespace and initial part of the URL path, you can extract that element from request.path (request.path.split('/')[1]) and set that as current_app in the request context, or just use it as the namespace in views.

http://docs.djangoproject.com/en/dev/topics/http/urls/#url-namespaces point 2.

You could do that e.g. in a context processor (if you want to use the namespace in a template).

For views you could write a decorator that feeds your function an extra kwarg “namespace” and use it as:

def view1(request, *args, **kwargs):
    ns = kwargs['namespace']

or just write a reverse_namespaced function with an extra param (the request) where the function gets the namespace from, and use it instead of reverse.

Of course if you do this you will always have to use a request path/namespace for this app


A lot has changed since the question was posted but for future googlers (like myself) it might be useful to point out that request has the namespace now (at least since 1.7 as shown in this example.

From what I understood we should be able to simply pass current_app positional argument to reverse/redirect but I couldn’t get it to work so I ended up creating an help method for this purpose:

def __redirect(request, viewname, *args, **kwargs):
    to = viewname

    if callable(to):
        to = viewname.__module__ + '.' + viewname.__name__
    if request.resolver_match.namespace:
        to = '%s:%s' % (request.resolver_match.namespace, to)

    return redirect(

I’m using redirect here but all the arguments are passed on to reverse, so it’s the same.


There is a doc page about reversing namespaced urls.


Either reverse('instance1:myapp.urls.some_view') or reverse('instance1:view_name') should work, or both 🙂 – i’ve never tried this myself.



The current_app variable is something you have to set yourself to something you like.

Personally I’d recommend setting it to something like __name__.rsplit('.', 1)[0] so you get spam in spam/views.py.

But you can define it to be anything you like, as long as your app name is consistent with what you define in your urls file.



If you’re not too tied to namespaces, you could instead write your urls.py to be like:

urlpatterns = patterns('',
    (r'^(P<instance>/)', 'controllers.route_me'),

This will make a call to the controllers.route_me function and pass it the request, plus the string ‘instance’, which you could handle this way:

# (in controllers.py)
def route_me(request, instance):
    # you now have complete control, and do what you need to do with the 'instance' and 'request' vars

Leave a comment