[Fixed]-TypeError: view must be a callable or a list/tuple in the case of include()

Replace your admin url pattern with this

url(r'^admin/', include(admin.site.urls))

So your urls.py becomes :

from django.conf.urls import url, include
from django.contrib import admin


urlpatterns = [
    url(r'^admin/', include(admin.site.urls)),
    url(r'^posts/$', "posts.views.post_home"), #posts is module and post_home 
] 

admin urls are callable by include (before 1.9).

For Django 1.11.2
In the main urls.py write :

from django.conf.urls import include,url
from django.contrib import admin

urlpatterns = [
    url(r'^admin/', admin.site.urls),
    url(r'^posts/', include("Post.urls")),
] 

And in the appname/urls.py file write:

from django.conf.urls import url
from . import views

urlpatterns = [
    url(r'^$',views.post_home),
]

Answer is in project-dir/urls.py

Including another URLconf
    1. Import the include() function: from django.conf.urls import url, include
    2. Add a URL to urlpatterns:  url(r'^blog/', include('blog.urls'))

Just to complement the answer from @knbk, we could use the template below:

as is in 1.9:

from django.conf.urls import url, include

urlpatterns = [
    url(r'^admin/', admin.site.urls), #it's not allowed to use the include() in the admin.urls
    url(r'^posts/$', include(posts.views.post_home), 
] 

as should be in 1.10:

from your_project_django.your_app_django.view import name_of_your_view

urlpatterns = [
    ...
    url(r'^name_of_the_view/$', name_of_the_view),
]

Remember to create in your_app_django >> views.py the function to render your view.

You need to pass actual view function

from posts.views import post_home

urlpatterns = [
…
url(r’^posts/$’, post_home),
]

This works fine!
You can have a read at URL Dispatcher Django
and here Common Reguler Expressions Django URLs