[Fixed]-Django – Override admin site's login form

Holá
I found a very simple solution.
You just need to modify the urls.py fle of the project (note, not the application one)

1. In your PROJECT folder locate the file urls.py.
2. Add this line to the imports section
   from your_app_name import views
3. Locate this line
   url(r'^admin/', include(admin.site.urls))
4. Add above that line the following
   url(r'^admin/login/', views.your_login_view),

This is an example

from django.conf.urls import include, url
from django.contrib import admin

from your_app import views

urlpatterns = [
    url(r'^your_app_start/', include('your_app.urls',namespace="your_app_name")),

    url(r'^admin/login/', views.your_app_login),
    url(r'^admin/', include(admin.site.urls)),
]

This code in urls.py works fine for me (Django version 1.5.1):

from django.contrib import admin
from my.forms import AuthenticationForm

admin.autodiscover()
admin.site.login_form = AuthenticationForm

I know this is an old thread, but I wanted to add something it helped me find, in case it can help others.

I’m using a special remote auth (Shibboleth) and overriding the admin login_form wouldn’t be enough. I have a view that sets cookies and return variables and redirects to the remote auth provider, etc.

So the way I did it was:

from my_app.views import user_login, user_logout
admin.autodiscover()
admin.site.login = user_login
admin.site.logout = user_logout

Works great!
Thanks to @dgk

I redirect to a unique login url (I’m using django 2.1 and python 3.6 f-strings):

from apps import admin
from django.urls import path, include
from django.shortcuts import redirect

urlpatterns = [
    path(
        'admin/login/',
        lambda r: redirect(
            f"/login?{r.META['QUERY_STRING']}" if r.META['QUERY_STRING'] \
            else '/login'
        )
    ),
    path('admin/', admin.site.urls),
]

Maybe use a templatetag to obtain your custom AuthenticationForm?