[Fixed]-Django: passing JSON from view to template

by

51👍

✅

If a frontend library needs a to parse JSON, you can use the json library to convert a python dict to a JSON valid string. Use the escapejs filter 

import json

def foo(request):
    json_string = json.dumps(<time_series>)
    render(request, "foo.html", {'time_series_json_string': json_string})


<script>
    var jsonObject = JSON.parse('{{ time_series_json_string | escapejs }}');
</script>
👤Yuji 'Tomita' Tomita

8👍

Pass a json.dumps value to the template. It is already a valid JSON string so you don’t need to parse it or anything. Only when rendering it in the template, mark it as safe to prevent HTML quoting.

# views.py
def foo(request):
    time_series_json = json.dumps(time_series)
    return render(request, 
                  "template.html", 
                  context={'time_series': time_series_json})

# in the template
<script>
    const timeSeries = {{ time_series | safe }};
</script>
👤Milan Cermak

4👍

Using the Django templates built-in filter json_script:

In views.py:

render(request, "foo.html", {'time_series_data': time_series})

In the template foo.html:

{{ time_series_data|json_script:"time-series-data" }}

In your script:

const timeSeriesData = JSON.parse(document.getElementById('time-series-data').textContent);
👤talz

2👍

have you tried passing something like json.dumps(time_series) to the render function?

👤Romeo Mihalcea

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